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 T O P I C    R E V I E W Haven Posted - 09/25/2008 : 08:52:23 The following information was given for the following problem:mx + nx + 16 = 0In the quadratic equation above, m and n are nonzero numbers. If the equation has only one solution, which of the following is equal to m in terms of n?The following answers given were:(a) m = n/2(b) m = n/4(c) m = n/16(d) m = n/16(e) m = n/ 64I need an explanation on how to solve this type of problem. Any assistance would be greatly appreciated. 2   L A T E S T    R E P L I E S    (Newest First) Haven Posted - 09/25/2008 : 14:35:01 Thanks again Skeeter. I thought about the general equation but for some reason the "m' and "n" threw me for a curve. Thanks again for all your help. skeeter Posted - 09/25/2008 : 11:17:53 the general quadratic is ...y = ax+bx+cif y = 0, then x = [-b [sqrt(b-4ac)]/(2a)further, if the quadratic equation has a single solution, then the discriminant, b-4ac, equals 0.in your problem ...a = mb = nc = 16work with that info.

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